8x^2-0,32=0

Solution for 8x^2-0,32=0 equation:

8x^2-0.32=0

a = 8; b = 0; c = -0.32;
Δ = b2-4ac
Δ = 02-4·8·(-0.32)
Δ = 10.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{10.24}}{2*8}=\frac{0-\sqrt{10.24}}{16}
=-\frac{\sqrt{}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{10.24}}{2*8}=\frac{0+\sqrt{10.24}}{16}
=\frac{\sqrt{}}{16}
$